Cuestion 9 (Efecto en corriente de colector de la variacion de la ganancia)


\begin{displaymath}I_{C_{2}}(\beta=100)=\frac{I_{ref}}{1+\frac{2}{100}}=\frac{100}{102}\,I_{ref}\end{displaymath}


\begin{displaymath}I_{C_{2}}(\beta=200)=\frac{I_{ref}}{1+\frac{2}{200}}=\frac{200}{202}\,I_{ref}\end{displaymath}




\begin{displaymath}\% =\frac{\frac{200}{202}-\frac{100}{102}}{\frac{200}{202}}\,100=0.98\,\%\end{displaymath}

La b) es la que mas se aproxima.