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COMPONENTES ELECTRONICOS Examenes 2005 Examenes 2006 Examenes 2007
Examenes 2008 Examenes 2009    

 

 

 

Cuestion 8


\begin{displaymath}I_{L}=100\, mA\end{displaymath}


\begin{displaymath}U_{s_{media}}=9\, V\end{displaymath}


\begin{displaymath}U_{e}=220\,V_{rms}\end{displaymath}


\begin{displaymath}f=50\,Hz\end{displaymath}


\begin{displaymath}U_{r_{pp}}=2\, V\end{displaymath}




\begin{displaymath}U_{s_{media}}\approx V_{p}-\frac{U_{r_{pp}}}{2}\end{displaymath}


\begin{displaymath}9=V_{p}-\frac{2}{2}\end{displaymath}


\begin{displaymath}V_{p}=10 \,V\end{displaymath}




cajael